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5th December 2011, 17:28
#1
Junior Member
PENDULUM F. M. Chalkalis - mathematical proof of the device's OU operation
PENDULUM F. M. Chalkalis - mathematical proof of the device's OU operation
PENDULUM F. M. Chalkalis - a talented inventor
? Kanarev FM
Contact the author: kanphil@mail.ru
Recommend that you review the video first http://chalkalis.blogspot.com/
Abstract.
F. M. Chalkalis, he says, invented the power multiplier, which converts electrical energy into mechanical energy with an index of energy efficiency, he believes, is ten times greater than one. http://chalkalis.blogspot.com/
View Video impresses with its visual results, but the calculation of these results, of course, wrong. The author and his advisers failed to properly calculate any amount of electrical energy consumed for the rotation of the pendulum, no amount of mechanical energy generated by the rotation of the pendulum. Their guilt in this, as new laws and new laws mehanodinamiki electrodynamics has not yet reached them. So help them by using the original data's experiment [1], [2].
Pendulum F. M. Chalkalis simple (Fig. 1).
image15568.gif
Two metal ball a total weight of 45.69 kg sectorial located at a distance of R = 0,51 m on the horizontal axis of rotation. This adds a lot of weight by frame on which are mounted balls. Weight 4.50 kg frame. The author does not hesitate to determine the moments of forces acting on the ball and the frame, by multiplying the mass of balls in the distance (R) from their centers of mass to the axis of rotation. Multiplying the result by the frequency of the pendulum, the author finds, as he believes the pendulum shaft power expressed in kilowatts. Since the mass of the frame is 10 times smaller than the mass of balls, then we remove it while in the calculation.Then the result is taken from the text of his article is as follows [3]:
Central weight F 45,69 Kg = 448,2 Ν ∙ r 0,51 m = 228.58Nm ∙ 160 RPM ? 9550 = 3,829 Κ w (1)
This result is valid only for the position of balls in the moments when the radii of their centers of mass to the rotation axis arranged horizontally. If the radii are vertical, then the moments of gravity acting on them with respect to the axis of rotation of the pendulum are equal to zero and the result (1) is also zero.
The video shows that the sector with the balls rotated uniformly. Based on this, unless you consider a sinusoidal nature of the change of the torque generated by balls in their rotation, according to the laws of mehanodinamiki, the kinetic energy of the uniform rotation with frequency 160ob./min balls. (Author's data of the experiment) is equal to [1], [2]
image15569.gif
and power at the shaft of the pendulum is
image15570.gif
urther, the author reports that the instruments were recorded consumption for the rotation of the two friction discs, which act on the impulse sector arc frame on which were mounted balls, showed the value of current image15571.gif and the voltage image15572.gif Multiplying them, the author receives power is being undertaken on a pendulum drive

and believes that the energy of the pendulum effect it is 3829 * 100/408 = 9385%.
Since the friction discs are the sector that keeps the balls from time to time, for the correct determination of the electric power sold to drive the pendulum, it was necessary to record the waveform of voltage and current. Determine the duty cycle of current pulses S and the voltage and the resulting value (4) divided by the square pulse duty cycle energy consumption. Visually (Fig. 1) we can assume that the sector is mounting balls, approximately one-fifth of 360 degrees, ie 360 / 5 = 72grad. Then the operating power, which is realized on the drive of the pendulum is equal to 408/25 = 16.32 Tues To this we must add the energy consumption by idling the motor, resulting in friction discs in the sector of 360-72 = 288grad. It will be approximately the same as in the workflow. Therefore, power, implemented on a uniform drive the pendulum is equal to 16.32 16.32 32.64 = Tues
As a result, energy efficiency, energy multiplier of copyright will be equal to approximately 1666.43 * 100/32, 64 = 5105%. We note that the voltage on the electric motor to drive the friction discs is equal to 24. If this voltage is generated with a voltage of 127V network, the meter shows the minimum capacity 127 * 17 = 2159Vt.
If the motors, resulting in friction discs, powered by a battery of 24V, the pulse power, taken from the battery, will be 32.64 Tues In this case, to recharge the battery must be taken from the network 32.64 W and the energy efficiency of idling pendulum is about 5000%.
Thus, in order to realize the explicit power pendulum effect F. M. Chalkalis, we must replace existing electric meters, which correctly take into account only the continuous consumption of electricity and erroneously - pulse. Then the energy of the pendulum effect will be close to 5000%. But the theoretical efficiency. If the pendulum to the shaft connecting the continuous load, it will be able to keep the regime of uniform rotation, if it is a much smaller initial value of 1666.43 Tues The exact magnitude of the load can only be determined experimentally for his own installation. However, the energy of the pendulum effect F. M. Chalkalis idling is undeniable. Of course, if you connect to the shaft of the pendulum impulse load, the efficiency multiplier of energy will increase in comparison with a continuous load.
CONCLUSION
There is reason to congratulate the inventor of F. M. Chalkalis with his inventive success, which buried the Newtonian dynamics and electrodynamics of Faraday - Maxwell ..
Literature
Kanarev FM Theoretical Mechanics. Part III Mehanodinamika. http://www.micro-world.su/ Folder "Textbooks"
Kanarev FM The introduction of the new electrodynamics. http://www.micro-world.su/ Folder "books"
http://chalkalis.blogspot.com/
http://www.micro-world.su/index.php/...m-chalkalis---
www.libero.it or http://www.micro-world.su/ folder "Video"
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